ÁÖ½Äȸ»ç½Å¿ìÅ×Å©

»ý»êÁ÷ (°è¾àÁ÷ 5 ~6°³¿ù)

Á÷¹«³»¿ë

-5°³¿ù ~6°³¿ù °è¾àÁ÷ (12¿ù~26³â 4¿ù)

-ÀüÀÚÁ¦Ç° Á¶¸³¿ø ¹× °ø¹«

-ÀÚ°ÝÁõ ¿ì´ë

*±â´É»ç*

Åë½Å±â±â,Åë½Å¼±·Î,Á¤º¸±â±â¿î¿ë,ÀüÆÄÀüÀÚÅë½Å,¹«¼±¼³ºñ,¹æ¼ÛÅë½Å,ÀüÀÚ±â±â(ÀüÀÚ),ÀüÀÚ°è»ê±â,ÀüÀÚijµå,Á¤º¸Ã³¸®,öµµÀü±â½ÅÈ£,±¤ÇÐ ¶Ç´Â ÀÇ·áÀüÀÚ

*»ê¾÷±â»ç*

Á¤º¸Åë½Å,ÀüÆÄÀüÀÚÅë½Å,¹«¼±¼³ºñ,Åë½Å¼±·Î,»ç¹«ÀÚµ¿È­,¹æ¼ÛÅë½Å,ÀüÀÚ,ÀüÀÚ°è»ê±âÁ¦¾î,¹ÝµµÃ¼¼³°è,Á¤º¸Ã³¸®,Åä¸ñ,öµµ½ÅÈ£,Á¤º¸º¸¾È,±¤Çбâ±â ¶Ç´Â Àǰø

±Ù¹«½Ã°£ ¹× ÇüÅÂ

ÁÖ 5ÀÏ ±Ù¹«

(±Ù¹«½Ã°£) (¿ÀÀü) 9½Ã 00ºÐ ~ (¿ÀÈÄ) 6½Ã 00ºÐ

ÁÖ¼ÒÁ¤±Ù·Î½Ã°£ : 40½Ã°£

±Þ¿©Á¶°Ç

- ¿ù±Þ 220¸¸¿ø ÀÌ»ó

ÀڰݸéÇã

- Á¤º¸Ã³¸®±â´É»ç

- Á¤º¸±â±â¿î¿ë±â´É»ç

Àå¾ÖÀÎä¿ëÈñ¸Á¿©ºÎ

ºñÈñ¸Á

º´¿ªÆ¯·Ê

- ºñÈñ¸Á

±âŸ Èñ¸Á³»¿ë

¾Æ·¡ÀÚ°ÝÁõº¸À¯ ¿ì´ë

*±â´É»ç*

Åë½Å±â±â,Åë½Å¼±·Î,Á¤º¸±â±â¿î¿ë,ÀüÆÄÀüÀÚÅë½Å,¹«¼±¼³ºñ,¹æ¼ÛÅë½Å,ÀüÀÚ±â±â(ÀüÀÚ),ÀüÀÚ°è»ê±â,ÀüÀÚijµå,Á¤º¸Ã³¸®,öµµÀü±â½ÅÈ£,±¤ÇÐ ¶Ç´Â ÀÇ·áÀüÀÚ

*»ê¾÷±â»ç*

Á¤º¸Åë½Å,ÀüÆÄÀüÀÚÅë½Å,¹«¼±¼³ºñ,Åë½Å¼±·Î,»ç¹«ÀÚµ¿È­,¹æ¼ÛÅë½Å,ÀüÀÚ,ÀüÀÚ°è»ê±âÁ¦¾î,¹ÝµµÃ¼¼³°è,Á¤º¸Ã³¸®,Åä¸ñ,öµµ½ÅÈ£,Á¤º¸º¸¾È,±¤Çбâ±â ¶Ç´Â Àǰø